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How to get a 5V signal out based on a sensor reading

Home Forums Mayfly Data Logger How to get a 5V signal out based on a sensor reading

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    • #15604
      Charitha (CJ)
      Participant

      I’m using a mayfly logger and trying to send out a 0-5V signal out to an actuator to be controlled using data collected thorough a CTD sensor (Hydros 21).  I have used the ‘DRWI_NoCellular.ino’ sketch referred in the monitoring station manual and was able to get the data logger to collect and store the data. I’ve been trying to figure out how to send out a signal. I read in some other forum answers that by setting D22 high/low I can change the voltage of the SW5 SW3 and grove terminals all together. However, the CTD sensor is connected to D6-7 (grove terminal) and being controlled by D22 in the sketch. Is there a way to do this? Maybe isolate the above terminals or something.

      Basically I’m trying to look at the water level reading from the CTD and based on a logical condition, send out a 0 or 5V signal out.

      This is my first arduino project. Any help is much appreciated. Thank you.

    • #15605
      Anthony Aufdenkampe
      Participant

      Check out this repo: https://github.com/EnviroDIY/Trigger

      This example sketch shows how it would be used in combination with the ModularSensors library: https://github.com/EnviroDIY/Trigger/blob/master/examples/simple_logging/simple_logging.ino

      It’s old, so some components are probably outdated, but it’s generally what you’re looking for.

       

    • #15608
      Shannon Hicks
      Participant

      What’s the duration of the 5v signal you want to generate?  And how much current does the 5v actuator draw?  Pin D22 controls the switched 3.3v and 5v outputs together, so there’s no way to separate the two.  However, a Hydros-21 CTD sensor uses very little current when it’s constantly powered, so you could plug the CTD into the D4-5 Grove jack, then move the jumper switch for the D4-5 jack over to the “3.3v” setting instead of the “3.3v Switched” setting, so the sensor would be constantly powered.  Be sure to change the CTD channel number in your sketch to “5” instead of “7”.  Your CTD sensor will now be constantly powered, but will only use measureable amounts of power when you send the SDI-12 command to take a reading, which most sketched do once every 5 minutes.  Then you could put the jumper on the D10-11 jack set to “5v switched” and when you turn on D22, the Grove jack’s Vcc pin will get 5 volts.  This would only work if you have no other sensors on the D22 line that you want to control.

      The other option would be to use a Grove relay board, like one of the ones from here: https://wiki.seeedstudio.com/Seeed_Relay_Page/ (only the ones with 3v excitation though) which would allow you to control a relay that’s capable of switching high current or high voltage signals.  But you’d still have to figure out where you’re getting the 5v signal, which again depends on how much current you’re trying to control and for how long.

      • #15611
        Charitha (CJ)
        Participant

        Thank you so much for the replies. The 5V signal duration varies with site and rain event conditions. However, with my previous field work, using a campbell system, the valve controlled by the actuator was open (5V) for an average of 10 mins (but could be a few hours on extreme rainfall events). How would the duration affect the mayfly? I’m using 12V (15AH) batteries to power the system. The actuator has separate power and signal inputs and the signal draws a very low current (I’m not quite sure how much however, the campbell loggers were able to provide it safely). I must note that the actuator actually requires a 0-10V signal and I’m thinking of using a PWM to voltage convertor (http://www.icstation.com/voltage-converter-module-adjustable-converter-power-module-digital-analog-signal-p-12498.html). Therefore, the signal from the mayfly will be directed in to the convertor, which has its own power supply to generate the 0-10V signal (if I understand it correctly).

        I hope I’m making sense. My knowledge is quite limited when it comes to electrical engineering.

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